eric

POTM 5 - Team 3 The Earth’s Circumference A steel band is placed around the earth, snugly fit at the equator. (The equator is approximately 25,000 miles in circumference.) This band is cut, and a 36 inch piece of string is added to the steel band. This new circular band is placed around the earth, hovering above the earth’s surface, with its center being the center of the earth. A gap is created between the equator and this circular band.

How wide is this gap?

1 - im very confused. can someone help me understand 2 - This question is looking for the gap between the new steel and the earth, if the string stays. A) the answer is 0, because the string gets squished and the steel goes back to how it was, or B) Let's say the Earth IS round and the diameter~25000/pi and the steel's diameter~(25000+3ft/5240)/pi. c=pi*D Get the radius by dividing 2 to both of the diameter, 0.5(25000/pi) and 0.5(25000+3ft/5240)/pi. Next subtract them, 0.5(132000003)/pi)-0.5(132000000/pi)=0.5(3/pi)=(0.5)0.95492965855137201461330258023509= 0.47746482927568600730665129011754ft.= 5.7295779513082320876798154814105 inches 3 - 4 -
 * __Class Member Contributions__**

 **// 1 point //**** State ** what the problem is looking for. How wide is the gap? The gap is 4.7 ft. from the equator to the steel. c=pi*D Get the radius by dividing 2 to both of the diameter, 0.5(25000/pi) and 0.5(25000+3ft/5240)/pi. Next subtract them, 0.5(132000003)/pi)-0.5(132000000/pi)=0.5(3/pi)=(0.5)0.95492965855137201461330258023509= 0.47746482927568600730665129011754ft.= 5.7295779513082320876798154814105 inches This is correct, because
 * // 2 points //**** Answer ** the problem correctly.
 * // 5 points //**** Explain the process ** you used to solve the problem.
 * // 2 points //**** Justify ** your answer. Type in the content of your page here.