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 * ​ ​Team 4**


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1 ** fly starts flying at 15 mi mark... horses are traveling at 8 mph and 7 mph. in 1 hr, horse 1 travels 8 mi and horse 2 travels 7 mi. 8+7=15, the horses will meet in an hour??? if they meet in an hour, the fly has 1 hour to fly. but it doesn't make sense to me that the fly would fly 25 miles, 25 mph... when it flies from one horse to the other, it already flies 15 mi in the beginning. **How many miles does the fly fly  ** (lol fly fly **) in a minute? ** || ** Team member 2 ** So far i think its 25 miles, but I'm not sure because the horses are getting closer together. I also know that you would make a R*T=D chart but i don't know what to put in it. Good- I think a R*T=D chart is good. t=1 though, because the horses will meet in an hour...I guess that means it //is// 25 miles! || 3 ** || **Team member 4 ** || it was confusing at first but then i kept reading it and took a little bit of information at a time and drew it out. at first i got 27 miles because i hit the 8 instead of the 5 on my calculator (on my itouch so its very hard to hit the right number), so when i checked the page to see what everyone else got, i re-checked my work, and noticed what i did. so //**__now__**// i got **25 miles.** **:]** || nothing made sense to me in the first place. but then i strated looking at how you guys solved the problem and ​person 1 you made it much clearer for me. so thanks a lot. when i looked at the rates in miles per minuet chart finding the answer made more sense to me. so i also agree its 25 miles. ||
 * ** Team member
 * < ** Team Member
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__25x__=__15__ 25 25 X=.6 36min = 24min 15mi = x mi
 * || Rate* || Time = || distance ||
 * fly || 25mph ||  x=1 || 25x ||
 * cross multiply 15 and 24=360/36=10

25 mi.
 * || Rate* || Time = || distance ||
 * fly || 25mph || <span style="color: #169ef8; font-family: 'Comic Sans MS',cursive;"> x<span style="color: #0e89ec; font-family: 'Comic Sans MS',cursive;">=1 || 25 ||

Rates in Miles per Minute horse 1- 8/60=0.13333333.../1 0.13333333333..... round to 0.13 miles per minute horse 2- 7/60= 0.1166666.../1 0.116666666666.....round to 0.12 miles per minute fly- 25/60= 0.416666666.../1 0.416666666666.....round to 0.42 miles per minute when you mult. this rate by 60, you get 25.

Two horses approach each other along the same country road, one walking at 8 mph, and the other at 7 mph. When the horses are 15 miles apart, a horsefly leaves one horse and flies at 25 mph towards the other. No sooner does the fly reach that horse than it turns around (losing no time on the turn) and returns to the first horse. If the fly continues to fly back and forth between the approaching horses, how far has the fly flown when the horses meet?
 * // 1 point //**** State ** what the problem is looking for.

<span style="color: #25a9e9; font-family: 'Comic Sans MS',cursive;">The problem is looking for the distance that the fly traveled in total when the horses met. <span style="color: #f50000; font-family: 'Times New Roman',Times,serif;">


 * // 2 points //**** Answer ** the problem correctly.

By the time the horses meet the fly would have flown 25 miles.

the fly has to fly for an hour because 8+7=15 and the fly starts flying when the horses are 15 miles apart. Now to find how much time it took the fly to fly 15 miles i made a R*T=D chart. the ending problem to solve was 25x=15 which came out to .6 or 36 minutes. Because there are 60 minutes in an hour i subtracted 36 from 60 and got 24. Now because i know that it flew 15 miles in 36 minutes i can make a proportion to find how far it flew in the remaining time(24 minutes). It would be 36 over 15 equals 24 over x. To solve it you would cross multiply 15 and 24 which came out to 360. Then I divided that by 36 and got 10. That means that in the remaining 24 minutes the fly flew 10 miles. then you would add up the total miles and get 25 miles.
 * // 5 points //**** Explain the process ** you used to solve the problem.


 * // 2 points //**** Justify ** your answer.