cow


 * Team 2**


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1 ** We can use the rate*time=distance formula. First we should find out how far the horses have traveled when they meet. And I'm thinking maybe we should try and "act" this out to see what should be done to solve the problem. (Don't have an "in-depth" thought of what to do, but those were just some general thoughts I should throw up. Yea.)
 * ** Team member

I created a picture of what this would look like: (sorry it took up so much space and like shrinked your writing/contributing spaces... If I made this picture any smaller, it would be unclear. ) (: || ** Team member 2 ** Thanks for the space! Anyway you would have to draw or act out the problem like Team Member 1 did. You would also have to create a distance rate and time chart. That's all I got... for now. =] || ** Team member 3 ** The picture helps a lot! Sorry this is late Wiki space was blocked on ​ my computer. I got the idea that they would meet in one hour and in one hour the fly would fly 25 miles. I still need a little help on how to get the answer in full explination and how to check it to make sure its right! Thanks! =) || ** Team member 4 ** Sorry this is late,but my wikispace was also blocked. The only part about the problem that I didnt get at first was the initial setting up of it.But after i used the R*T=D chart and i understood it. Also, I think the picture really helped alot. || Then I created the equation 7x+8x=15 because the distance horse 1 traveled and the distance horse 2 traveled (until they meet) add up to 15. After solving this equation, I got that x=1, which means that it will take them an hour to meet. Then, I decided to find how far the fly would travel in one hour, because in one hour the horseys will meet. So, I set up the table... ||  || R* || T= || D ||   || Fly ||   || 25 ||   || 1 ||   ||   ||
 * Okay, I think I might have it. I'm still reviewing and I'm not sure but this is what I have... I set up a table...

The formula for distance is rate x time, and 25 times 1 is 25, so the fly traveled 25 miles.

I'm still reviewing, I'm not sure if this is right. I don't know if this answer is showing if the fly went back and forth... I'll look over it.

Oh no, sorry I don't know what happened, the tables I made got all messed up. Sorry for the mess... :) || || R* || T= || D ||
 * Horse 1 || 7 || x ||  ||
 * Horse 2 || 8 || x ||  ||

Two horses approach each other along the same country road, one walking at 8 mph, and the other at 7 mph. When the horses are 15 miles apart, a horsefly leaves one horse and flies at 25 mph towards the other. No sooner does the fly reach that horse than it turns around (losing no time on the turn) and returns to the first horse. If the fly continues to fly back and forth between the approaching horses, how far has the fly flown when the horses meet? How far the fly has flown if it flys back and forth between the two approaching horses.
 * // 1 point //**** State ** what the problem is looking for.

The fly has flown 25 miles. To solve this problem, we first set up a table to find out how much time it would take for the two horses to meet when they are 15 miles apart. So, we set up a table. We then created the equation 7x + 8x = 15, because the distance Horse 1 traveled and the distance Horse 2 traveled added together must equal 15 miles to meet when they are 15 miles apart. We then got that x = 1, so that means that it will take the horses 1 hour to meet. Then, we set up a table to determine how far the fly would travel. Then, the equation is 25(1)=x. x = 25. So, in one hour, which is how long it will take the horses to meet, the fly will have traveled 25 miles.
 * // 2 points //**** Answer ** the problem correctly.
 * // 5 points //**** Explain the process ** you used to solve the problem.
 * || R * || T= || D ||
 * Horse 1 || 7 || x ||  ||
 * Horse 2 || 8 || x ||  ||
 * || R* || T= || D ||
 * Fly || 25 || 1 || x ||

I think our answer is reasonable, and I think the process we took to answer it was logical.
 * // 2 points //**** Justify ** your answer.